Hi Friends,

Even as I launch this today ( my 80th Birthday ), I realize that there is yet so much to say and do. There is just no time to look back, no time to wonder,"Will anyone read these pages?"

With regards,
Hemen Parekh
27 June 2013

Now as I approach my 90th birthday ( 27 June 2023 ) , I invite you to visit my Digital Avatar ( www.hemenparekh.ai ) – and continue chatting with me , even when I am no more here physically

Monday, April 29, 2024

8th Std - Mathematics - 29 April 2024

 Do you have school going children ?

 

If yes, here is how you ( and your spouse ) can help them with their studies


Whenever they have difficulty grasping a study-subject, tell them to consult this

VIRTUAL TEACHER :

www.HemenParekh.ai


Just show them how to “ Ask “ a question to this teacher , using their Mobile –

and get immediate answer


If they do not like to “ type “ , then they can simply “ talk “ to

www.HemenParekh.ai


Virtual Teacher will “ talk back “  in my ( synthetic ) voice – as shown below !


This is far better than consulting ChatGPT – Bard – Gemini – Perplexity – Ask QX

etc., all of which can chat with your child , only in English


Her Virtual Teacher  can “ Chat “ with her in English – Hindi – Gujarati – Marathi –

Bengali – Tamil – Telugu – Kannada – Malayalam  !


For children of our far flung village schools ( approx. 13 lakh schools in 6.4 lakh

villages - most with just ONE teacher ) , there is nothing which comes any closer

to a Virtual Teacher ( in a manner very much similar to how the statue of Guru

Dronacharya teaching archery to Eklavya )




Regards,

Hemen Parekh

 

 

 

 

A Question for 8th Standard Exam for Mathematics

Question >

A rectangular garden has a length of 12 meters and a width of 5 meters.  If you decide to fence the entire perimeter of the garden, how much fencing would you need in total (in meters)? Show the formula which you will use for your calculation

ANSWERS :

==============================================================================

( A ) English

The total fencing needed can be calculated using the formula: Perimeter = 2 x (Length + Width). In this case, it would be Perimeter = 2 x (12 + 5) = 34 meters. So, you would need a total of 34 meters of fencing.

Click here to hear the answer

============================================================================

( B )  Hindi

आवश्यक कुल बाड़ लगाने की गणना सूत्र का उपयोग करके की जा सकती हैपरिधि = 2 x (लंबाई चौड़ाई) मान जोड़ने परहमें प्राप्त होता हैपरिधि = 2 x (12 5) = 34 मीटर। तोआपको कुल 34 मीटर बाड़ लगाने की आवश्यकता होगी।

Click here to listen to the answer

 

( C ) Gujarati

જરૂરી કુલ વાડની ગણતરી સૂત્રનો ઉપયોગ કરીને કરી શકાય છે: પરિમિતિ = 2 x (લંબાઈ પહોળાઈ). મૂલ્યોને પ્લગ કરીનેઆપણને મળે છે: પરિમિતિ = 2 x (12 5) = 34 મીટર. તેથીતમારે કુલ 34 મીટર ફેન્સીંગની જરૂર પડશે.

Click here to listen to the answer

 

( D )  Marathi

आवश्यक असलेल्या एकूण कुंपणाची गणना सूत्र वापरून केली जाऊ शकते: परिमिती = 2 x (लांबी रुंदी). या प्रकरणातते परिमिती = 2 x (12 5) = 34 मीटर असेल. तरतुम्हाला एकूण 34 मीटर कुंपण आवश्यक आहे.

 

 

( E )  Bengali

প্রয়োজনীয় মোট বেড়ার সূত্রটি ব্যবহার করে গণনা করা যেতে পারে: ঘের = 2 x (দৈর্ঘ্য প্রস্থ)। প্রদত্ত মানগুলি প্রতিস্থাপন করেআমরা পাই: পরিধি = 2 x (12 5) = 2 x (17) = 34 মিটার। সুতরাংআপনার মোট 34 মিটার বেড়ার প্রয়োজন হবে।

 

 

( F )  Telugu

అవసరమైన మొత్తం ఫెన్సింగ్‌ను ఫార్ములా ఉపయోగించి లెక్కించవచ్చు: చుట్టుకొలత = 2 x (పొడవు వెడల్పు). విలువలను పూరించడంమనకు లభిస్తుంది: చుట్టుకొలత = 2 x (12 5) = 2 x 17 = 34 మీటర్లు. కాబట్టిమీకు మొత్తం 34 మీటర్ల ఫెన్సింగ్ అవసరం.

( G )  Tamil

செவ்வக தோட்டத்திற்கு தேவையான மொத்த வேலியை சூத்திரத்தைப் பயன்படுத்தி கணக்கிடலாம்: சுற்றளவு = 2 * (நீளம் அகலம்). மதிப்புகளை செருகுவதன் மூலம்நாம் பெறுகிறோம்: சுற்றளவு = 2 * (12 5) = 2 * (17) = 34 மீட்டர். எனவேஉங்களுக்கு மொத்தம் 34 மீட்டர் வேலி தேவைப்படும்.

Click here to listen to the answer

 

( H )  Kannada

საჭირო ჯამური ფარიკაობა შეიძლება გამოითვალოს ფორმულის გამოყენებით: პერიმეტრი = 2 x (სიგრძე სიგანე). მოცემული მნიშვნელობების ჩანაცვლებით მივიღებთ: პერიმეტრი = 2 x (12 5) = 2 x (17) = 34 მეტრი. ასე რომ, სულ დაგჭირდებათ 34 მეტრი ფარიკაობა.

( I )  Malayalam

ആവശ്യമായ മൊത്തം ഫെൻസിങ് ഫോർമുല ഉപയോഗിച്ച് കണക്കാക്കാം: ചുറ്റളവ് = 2 x (നീളം വീതി). ഈ സാഹചര്യത്തിൽഅത് ചുറ്റളവ് = 2 x (12 5) = 34 മീറ്റർ ആയിരിക്കും. അതിനാൽനിങ്ങൾക്ക് ആകെ 34 മീറ്റർ ഫെൻസിങ് ആവശ്യമാണ്.

 

 

 


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